(1/16)=64^(3x+5)

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Solution for (1/16)=64^(3x+5) equation: 



(1/16)=64^(3x+5)

We move all terms to the left:

(1/16)-(64^(3x+5))=0

We add all the numbers together, and all the variables

-(64^(3x+5))+(+1/16)=0

We get rid of parentheses

-(64^(3x+5))+1/16=0

We multiply all the terms by the denominator


-((64^(3x+5)))*16+1=0

We move all terms containing x to the left, all other terms to the right

-((64^(3x+5)))*16=-1

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